【Leetcode 38】报数

【Leetcode 38】报数

class Solution: def countAndSay(self, n: int) -> str: prev_person = '1' for i in range(1,n): next_person, num, count = '', prev_person[0], 1 for j in range(1,len(prev_person)): if prev_person[j] == num:count += 1 else: next_person += str(count) + num num = prev_person[j] count = 1 next_person += str(count) + num prev_person = next_person return prev_person

参考链接​​​ https://leetcode-cn.com/problems/count-and-say/solution/ji-su-jie-bu-di-gui-zhi-ji-lu-qian-hou-liang-ren-p/​​

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