[leetcode] 1576. Replace All ?‘s to Avoid Consecutive Repeating Characters

[leetcode] 1576. Replace All ?‘s to Avoid Consecutive Repeating Characters

Description

Given a string s containing only lower case English letters and the ‘?’ character, convert all the ‘?’ characters into lower case letters such that the final string does not contain any consecutive repeating characters. You cannot modify the non ‘?’ characters.

It is guaranteed that there are no consecutive repeating characters in the given string except for ‘?’.

Return the final string after all the conversions (possibly zero) have been made. If there is more than one solution, return any of them. It can be shown that an answer is always possible with the given constraints.

Example 1:

Input: s = "?zs"Output: "azs"Explanation: There are 25 solutions for this problem. From "azs" to "yzs", all are valid. Only "z" is an invalid modification as the string will consist of consecutive repeating characters in "zzs".

Example 2:

Input: s = "ubv?w"Output: "ubvaw"Explanation: There are 24 solutions for this problem. Only "v" and "w" are invalid modifications as the strings will consist of consecutive repeating characters in "ubvvw" and "ubvww".

Example 3:

Input: s = "j?qg??b"Output: "jaqgacb"

Example 4:

Input: s = "??yw?ipkj?"Output: "acywaipkja"

Constraints:

1 <= s.length <= 100s contains only lower case English letters and ‘?’.

分析

题目的意思是：给定一个字符串s，替换s中的问号，使得替换后相邻的字符不相同。 思路很直接，遍历找合适的字符替换问号，需要注意边界的问题。

代码

class Solution: def modifyString(self, s: str) -> str: res='' n=len(s) if(n==1 and s=='?'): return 'a' for i,ch in enumerate(s): if(ch=='?'): if(i==0 and i

参考文献

​​[LeetCode] Python 3 Solution for Beginners ( 3 letter soln)​​

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