mysql select查询基本运算符练习题

网友投稿 841 2022-08-30

mysql select查询基本运算符练习题

mysql select查询基本运算符练习题

# 1.选择工资不在5000到12000的员工的姓名和工资

SELECT last_name ,salary

FROM employees

WHERE salary BETWEEN 5000 AND 12000;

#第二种写法

SELECT  last_name ,salary

FROM employees

WHERE salary >=5000 AND salary <=12000;

# 2.选择在20或50号部门工作的员工姓名和部门号

SELECT last_name ,department_id

FROM employees

WHERE department_id IN (20,50);

SELECT last_name,department_id

FROM employees

WHERE department_id=20 OR department_id=50;

# 3.选择公司中没有管理者的员工姓名及job_id

DESC employees;

SELECT last_name ,job_id ,manager_id

FROM employees

WHERE manager_id IS NULL

SELECT last_name ,job_id,manager_id

FROM employees

WHERE manager_id <=> NULL

SELECT last_name ,job_id ,manager_id

FROM employees

WHERE ISNULL(manager_id)

# 4.选择公司中有奖金的员工姓名,工资和奖金级别

SELECT last_name ,salary ,commission_pct

FROM employees

WHERE commission_pct IS NOT NULL

# 5.选择员工姓名的第三个字母是a的员工姓名

SELECT last_name

FROM employees

WHERE last_name LIKE '__a%';

# 6.选择姓名中有字母a和k的员工姓名

SELECT last_name

FROM employees

WHERE last_name LIKE '%a%' AND last_name LIKE '%k%'

SELECT last_name

FROM employees

WHERE last_name LIKE '%a%' && last_name LIKE '%k%'

SELECT last_name

FROM employees

WHERE last_name LIKE '%a%k%' OR last_name LIKE '%k%a%';

#7.显示出表 employees 表中 first_name 以 'e'结尾的员工信息

SELECT first_name

FROM employees

WHERE first_name RLIKE 'e$'

SELECT first_name

FROM employees

WHERE first_name REGEXP 'e$'

# 8.显示出表 employees 部门编号在 80-100 之间的姓名、工种

SELECT last_name,job_id,department_id

FROM employees

WHERE department_id BETWEEN 80 AND 100;

# 9.显示出表 employees 的 manager_id 是 100,101,110 的员工姓名、工资、管理者id

SELECT last_name ,salary,manager_id

FROM employees

WHERE manager_id IN (100,101,110);

版权声明:本文内容由网络用户投稿,版权归原作者所有,本站不拥有其著作权,亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容,请联系我们jiasou666@gmail.com 处理,核实后本网站将在24小时内删除侵权内容。

上一篇:map 并发崩溃一例:顺便吐槽 Go 打印堆栈不友好(map医学上)
下一篇:mysql 基础运算符范例
相关文章

 发表评论

暂时没有评论,来抢沙发吧~