1547D - Co-growing Sequence

网友投稿 479 2022-12-01

1547D - Co-growing Sequence

1547D - Co-growing Sequence

// Problem: D. Co-growing Sequence// Contest: Codeforces - Codeforces Round #731 (Div. 3)// URL: Memory Limit: 512 MB// Time Limit: 2000 ms// 2022-02-19 15:00:11// // Powered by CP Editor (namespace std;#define rep(i,l,r) for(int i=(l);i<=(r);i++)#define per(i,l,r) for(int i=(l);i>=(r);i--)#define ll long long#define pii pair#define mset(s,t) memset(s,t,sizeof(t))#define mcpy(s,t) memcpy(s,t,sizeof(t))#define fir first#define pb push_back#define sec second#define sortall(x) sort((x).begin(),(x).end())inline int read () { int x = 0, f = 0; char ch = getchar(); while (!isdigit(ch)) f |= (ch=='-'),ch= getchar(); while (isdigit(ch)) x = x * 10 + ch - '0', ch = getchar(); return f?-x:x;}template void print(T x) { if (x < 0) putchar('-'), x = -x; if (x >= 10) print(x/10); putchar(x % 10 + '0');}int n;int a[200005];int b[200005];void solve() { cin >> n; for (int i = 1; i <= n; i ++) cin >> a[i]; b[1] = 0; memset(b, 0, sizeof b); for (int i= 2; i <= n; i ++) { int ans = 0; for (int j= 0; j <= 30; j ++) { if (!(a[i] >> j & 1) && ((a[i - 1] ^ b[i - 1]) >> j & 1)) { b[i] += pow(2, j); } } } for (int i = 1; i<= n; i ++) cout << b[i] << " \n"[i == n];}int main () { int t; cin >> t; while (t --) solve(); return 0;}

通过让首位最小,然后后面的就确定了。整个序列一定是最小的且唯一的

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