ASCII字符显示例子

ASCII字符显示例子

代码块

#include#include//算法是最费心思，也是最有趣的事情了，char字符也很有趣，使用字符画矩形。//简单的程序很多问题，不过乐乐而已int main(void){ FILE *fp;//保存的文件 int i, total;//字符总数 int row, col;//行列数 char ch; //初始字符 char count[80][80];//字符矩阵 puts("Enter the total of rings: "); scanf("%d", &total); ch = 32; for (row = 1; row <= 2 * total; row++) for (col = 1; col <= 2 * total; col++) count[row][col] = 0; //置空数组 //row:1…n // col:1…n // v[r,c]=0 /*利用循环语句分别输出上下左右四条边，注意每个圈往里缩一个位置*/ for (i = 1; i <= total; i++) { row = i; for (col = i + 1; col <= 2 * total - i; col++)//绘制倒三角，上边框 { count[row][col] = ch; } row = 2 * total - i + 1; for (col = i + 1; col <= 2 * total - i; col++)//绘制正三角，下边框 { count[row][col] = ch; } col = i; for (row = i; row <= 2 * total - i + 1; row++)//绘制左三角，左边框 { count[row][col] = ch; } col = 2 * total - i + 1; for (row = i; row <= 2 * total - i + 1; row++)//绘制右三角，右边框 { count[row][col] = ch; } ch++; } /*利用判断语句输出上下左右四条边，注意每个圈往里缩一个位置*/ for (i = 1; i <= total; i++) { for (row = i; row <= 2 * total - i; row++) for (col = i; col <= 2 * total - i; col++) if (row == i || row == 2 * total - i || col == i || col == 2 * total - i) count[row][col] = ch; ch++; } if ((fp = fopen("sdas.txt", "w")) == NULL) { fprintf(stderr, "\nError opening file \n"); exit(1); } /*输出数组（即图案）*/ for (row = 1; row <= 2 * total; row++) { for (col = 1; col <= 2 * total; col++) { fprintf(fp, "%c ", count[row][col]);//输出到文件， fprintf(stdout, "%c ", count[row][col]);//输出到屏幕 } fprintf(fp, "\n"); fprintf(stdout, "\n"); } system("pause"); return 0;}

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