[leetcode] 385. Mini Parser
[leetcode] 385. Mini Parser
Description
Given a nested list of integers represented as a string, implement a parser to deserialize it.
Each element is either an integer, or a list – whose elements may also be integers or other lists.
Note: You may assume that the string is well-formed:
String is non-empty. String does not contain white spaces. String contains only digits 0-9, [, - , ]. Example 1:
Given s = "324",You should return a NestedInteger object which contains a single integer 324.
Example 2:
Given s = "[123,[456,[789]]]",Return a NestedInteger object containing a nested list with 2 elements:1. An integer containing value 123.2. A nested list containing two elements: i. An integer containing value 456. ii. A nested list with one element: a. An integer containing value 789.
分析
题目的意思是:序列化一个嵌套的字符串。
首先判断s是否为空,为空直接返回,不为空的话看首字符是否为’[’,不是的话说明s为一个整数,我们直接返回结果。如果首字符是’[’,且s长度小于等于2,说明没有内容,直接返回结果。反之如果s长度大于2,我们从i=1开始遍历,我们需要一个变量start来记录某一层的起始位置,用cnt来记录跟起始位置是否为同一深度,cnt=0表示同一深度,由于中间每段都是由逗号隔开,所以当我们判断当cnt为0,且当前字符是逗号或者已经到字符串末尾了,我们把start到当前位置之间的字符串取出来递归调用函数,把返回结果加入res中,然后start更新为i+1。如果遇到’[’,计数器cnt自增1,若遇到’]’,计数器cnt自减1。
代码
/** * // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * class NestedInteger { * public: * // Constructor initializes an empty nested list. * NestedInteger(); * * // Constructor initializes a single integer. * NestedInteger(int value); * * // Return true if this NestedInteger holds a single integer, rather than a nested list. * bool isInteger() const; * * // Return the single integer that this NestedInteger holds, if it holds a single integer * // The result is undefined if this NestedInteger holds a nested list * int getInteger() const; * * // Set this NestedInteger to hold a single integer. * void setInteger(int value); * * // Set this NestedInteger to hold a nested list and adds a nested integer to it. * void add(const NestedInteger &ni); * * // Return the nested list that this NestedInteger holds, if it holds a nested list * // The result is undefined if this NestedInteger holds a single integer * const vector 参考文献 [LeetCode] Mini Parser 迷你解析器
版权声明:本文内容由网络用户投稿,版权归原作者所有,本站不拥有其著作权,亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容,请联系我们jiasou666@gmail.com 处理,核实后本网站将在24小时内删除侵权内容。
发表评论
暂时没有评论,来抢沙发吧~