[leetcode] 1523. Count Odd Numbers in an Interval Range

[leetcode] 1523. Count Odd Numbers in an Interval Range

Description

Given two non-negative integers low and high. Return the count of odd numbers between low and high (inclusive).

Example 1:

Input: low = 3, high = 7Output: 3Explanation: The odd numbers between 3 and 7 are [3,5,7].

Example 2:

Input: low = 8, high = 10Output: 1Explanation: The odd numbers between 8 and 10 are [9].

Note:

0 <= low <= high <= 10^9.

分析

题目的意思是：求出给定区间[low,high]中奇数的个数。思路很直接，我把low和high的奇偶性单独拿出来判断，剩下的按照奇偶各一半的思路，直接求出来就行了。

我看了一下别人的解法，直接判断从1开始以low和hight结尾的奇数个数，然后相减就行了，思路很好。(high + 1) / 2 - low / 2

代码

class Solution: def countOdds(self, low: int, high: int) -> int: res=0 if(low%2==1): low+=1 res+=1 if(high%2==1): high-=1 res+=1 res+=(high-low)//2 return res

参考文献

[Java/C++/Python] 1-Lines](https://leetcode.com/problems/count-odd-numbers-in-an-interval-range/discuss/754726/JavaC%2B%2BPython-1-Lines)

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