[leetcode] 1507. Reformat Date

[leetcode] 1507. Reformat date

Description

Given a date string in the form Day Month Year, where:

Day is in the set {“1st”, “2nd”, “3rd”, “4th”, …, “30th”, “31st”}.Month is in the set {“Jan”, “Feb”, “Mar”, “Apr”, “May”, “Jun”, “Jul”, “Aug”, “Sep”, “Oct”, “Nov”, “Dec”}.Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

YYYY denotes the 4 digit year.MM denotes the 2 digit month.DD denotes the 2 digit day.

Example 1:

Input: date = "20th Oct 2052"Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"Output: "1960-05-26"

Constraints:

The given dates are guaranteed to be valid, so no error handling is necessary.

分析

题目的意思是：把英文日期格式转换成用横线分隔符号的日期形式，我的想法很简单，就是字符串拼接了哈。

代码

class Solution: def reformatDate(self, date: str) -> str: months=["Jan","Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"] day,month,year=date.split() m='' for i in range(len(months)): if(months[i]==month): m=str(i+1) d='' for ch in day: if(ch>='0' and ch<='9'): d+=ch if(int(d)<10): d='0'+d if(int(m)<10): m='0'+m return year+'-'+m+'-'+d

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