686. Repeated String Match

686. Repeated String Match

Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1.

For example, with A = “abcd” and B = “cdabcdab”.

Return 3, because by repeating A three times (“abcdabcdabcd”), B is a substring of it; and B is not a substring of A repeated two times (“abcdabcd”).

Note: The length of A and B will be between 1 and 10000.

class Solution { public int repeatedStringMatch(String A, String B) { String t = A ; for(int i = 1 ; i <= B.length()/A.length()+2 ; i++){ if (t.indexOf(B) != -1) return i ; else t += A

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