Problem 30 Digit fifth powers （暴力枚举）

Problem 30 Digit fifth powers （暴力枚举）

Digit fifth powers

Problem 30

Surprisingly there are only three numbers that can be written as the sum of fourth powers of their digits:

1634 = 14 + 64 + 34 + 44 8208 = 84 + 24 + 04 + 84 9474 = 94 + 44 + 74 + 44

As 1 = 14 is not a sum it is not included.

The sum of these numbers is 1634 + 8208 + 9474 = 19316.

Find the sum of all the numbers that can be written as the sum of fifth powers of their digits.

题解：如果是一个6位数，各位数字5次方之和最大为 6 * 95 = 354294，是一个6位数，所以6位数是有可能满足的。 如果是一个7位数，各位数字5次方之和最大为 7 * 95 = 413343，是一个6位数，不可能等于7位数自身，所以7位数是不可能满足的。注意：As 1 = 14 is not a sum it is not included..

代码：

#includeint sum(int n){ int sum=0; int digit = 0; while(n!=0) { digit = n%10; sum += (int)pow((float)digit,5); n /= 10; } return sum;}int main(){ int i; int ans = 0; for (i=10;i<999999;i++) { if (sum(i) == i) { ans += i; } } std::cout<

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