LeetCode-174. Dungeon Game

网友投稿 593 2022-10-03

LeetCode-174. Dungeon Game

LeetCode-174. Dungeon Game

The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way through the dungeon to rescue the princess.

The knight has an initial health point represented by a positive integer. If at any point his health point drops to 0 or below, he dies immediately.

Some of the rooms are guarded by demons, so the knight loses health (negative integers) upon entering these rooms; other rooms are either empty (0's) or contain magic orbs that increase the knight's health (positive integers).

In order to reach the princess as quickly as possible, the knight decides to move only rightward or downward in each step.

Write a function to determine the knight's minimum initial health so that he is able to rescue the princess.

For example, given the dungeon below, the initial health of the knight must be at least 7 if he follows the optimal path ​​RIGHT-> RIGHT -> DOWN -> DOWN​​.

-2 (K)

-3

3

-5

-10

1

10

30

-5 (P)

题解:左上到右下的dp没做出来,貌似必须逆向。

左上到右下,通过32个测试,陷入局部最优解:

class Solution {public: int calculateMinimumHP(vector>& dungeon) { if (dungeon.empty() == true) { return 0; } int n = dungeon.size(), m = dungeon[0].size(); vector> dp(n, vector(m, 0)); vector> path(dungeon); dp[0][0] = dungeon[0][0]; for (int i = 1; i < n; i++) { path[i][0] += path[i - 1][0]; dp[i][0] = min(dp[i - 1][0], path[i][0]); } for (int j = 1; j < m; j++) { path[0][j] += path[0][j - 1]; dp[0][j] = min(dp[0][j - 1], path[0][j]); } for (int i = 1; i < n; i++) { for (int j = 1; j < m; j++) { int tmp1, tmp2; if (dp[i - 1][j] > dp[i][j - 1]) { path[i][j] += path[i - 1][j]; tmp1 = min(dp[i - 1][j], path[i][j]); tmp2 = dp[i][j - 1]; } else { path[i][j] += path[i][j - 1]; tmp1 = min(dp[i][j - 1], path[i][j]); tmp2 = dp[i - 1][j]; } dp[i][j] = max(tmp1, tmp2); } } if (dp[n - 1][m - 1] > 0) { return 1; } return -dp[n - 1][m - 1] + 1; }};

逆向寻找ac:

class Solution {public: int calculateMinimumHP(vector>& dungeon) { if (dungeon.empty() == true) { return 0; } int n = dungeon.size(), m = dungeon[0].size(); vector> dp(n + 1, vector(m + 1, INT_MAX)); dp[n - 1][m] = 1; dp[n][m - 1] = 1; for (int i = n - 1; i >= 0; i--) { for (int j = m - 1; j >= 0; j--) { int value = min(dp[i][j + 1], dp[i + 1][j]) - dungeon[i][j]; if (value > 0) { dp[i][j] = value; } else { dp[i][j] = 1; } } } return dp[0][0]; }};

版权声明:本文内容由网络用户投稿,版权归原作者所有,本站不拥有其著作权,亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容,请联系我们jiasou666@gmail.com 处理,核实后本网站将在24小时内删除侵权内容。

上一篇:小程序登录和授权有什么不同
下一篇:小程序网页能登入么(小程序能打开网页吗)
相关文章

 发表评论

暂时没有评论,来抢沙发吧~